Java program to find disarium number

This is our complied and working program for disarium number

A number is called Disarium if sum of its digits powered with their respective positions is equal to the number itself.

import java.io.*;

class Disarium

    {

    public static void main(String[] args)throws IOException

        {

            BufferedReader br=newBufferedReader (new InputStreamReader(System.in));

            System.out.print("Enter a number : ");

            int n = Integer.parseInt(br.readLine());

            int copy = n, d = 0, sum = 0;

            String s = Integer.toString(n); //converting the number into a String

            int len = s.length(); //finding the length of the number i.e. no.of digits

            

            while(copy>0)

            {

                d = copy % 10; //extracting the last digit

                sum = sum + (int)Math.pow(d,len);

                len--;

                copy = copy / 10;

            }

            

            if(sum == n)

                System.out.println(n+" is a Disarium Number.");

            else

                System.out.println(n+" is not a Disarium Number.");

        }

}